All Star Catching Mitts, Write a polynomial to represent the area of each . - YouTube. About featured snippets•FeedbackQuestions & answersBrainly.comQuestionWrite a polynomial that represents the area of the square.Answer · 10 votesAnswer:The answer to your question is Area = 49n² - 70n + 25 Step-by-step explanation:DataLength of the side = 7n - 5FormulaArea of a square = side x sideProcess1.- Substitute valuesArea = (7n - 5)(7n - 5)2.- ExpandArea = 49n² - 35n - 35n + 253.- SimplifyArea = 49n² - 70n + 25 4.- The polynomial is 49n² - 70n + 25MoreGauthmathQuestionWrite a polynomial that represents the area of the square. The polynomial is 1.Answer · 144 votesAnswer: .MoreCheggQuestionWrite a polynomial that represents the area of the square. The polynomial isAnswer · 0 votesSolve for the polynomial that represents the.MoreNumeradeQuestion'Write a polynomial that represents the area of the square.'Answer · 4 votesSo in this problem we are asked to find a polynomial that represents the area of the square and the formula for area of a square is side squared. I'm gonna do a equals seven N -5 squared and to square this, you have to write this twice in foil, So that gives us 49 and squared -35, then -35, and again last 25. And if we combine the like terms that's 49 and squared -70 and plus 25 which is the equation for the area of the square.MoreBartleby.comQuestionMATHEMATICAL CONNECTIONS Write a polynomial that represents the area of the square.4c + 4dThe polynomial isAnswer · 0 votesStep 1 Given:.MoreNumeradeQuestionWrite a polynomial expression that represents the total area of a square with a side length of (3x - 4).Answer · 2 votesfor this exercise, we're given the above square with one of its sides labeled as two X plus three. And then we want to find a polynomial that represents the area of the square. Now recall that in a square. All four sides are can be equal. So if they're telling us that one side is two X plus three, that means every other side is also two X plus three. Which is going to be helpful for finding the area to find area of square. All you need to do is to Square one of the sides. That is you're going to raise the length of one of the sides to the power of two if you prefer to think of it as length times width, the length and the width are the same here. They're both two X plus three. So we're gonna be doing the calculation two x plus three, multiplied by two x plus three. Because in each of these parentheses we have two separate terms. We need to be careful that we're multiplying each term in one parentheses by each term in the other. You may hear this referred to as foil method, which helps y…MoreQuizletQuestionShow one or more circles drawn inside a square. Write a polynomial that represents the shaded blue area in each figure. Then factor the polynomial.Answer · 0 votesThe goal of this task is to write a polynomial that represents the shaded blue area in given figure. To do so use formula for area of square$$A=acdot a=a^2$$where $a$ is the side of square, and formula for area of a circle$$A=r^2cdot pi$$where $r$ is radius of a circle. **Find area of the square:**From the given image we can see that the side of the square is $a=6x$, by substituting we have:$$begin{aligned}A&=acdot a&text{Area of the square}&=6xcdot 6x&text{Substitute}&=36x^2&text{Multiply}end{aligned}$$$Rightarrow$ The area of ​​the square is $A=36x^2$. **Find area of a circle:**From the given image we can see that the radius of a circle is $r=2x$, by substituting we have:$$begin{aligned}A&=r^2pi&text{Area of a circle}&=(2x)^2pi&text{Substitute}&=2xcdot 2xcdot pi&=4x^2cdot 3.14&text{Substitute $pi=3.14$}&=12.56x^2&text{Multiply}end{aligned}$$$Rightarrow$ The area of a circle is $A=12.56x^2$. ***Now we can find area of shaded blue …MorePearsonQuestionIn Exercises 53–54, write a polynomial that represents the length of each rectangle.Transcription: The area of the rectangle is 0.5x^3 - 0.3x^2 + 0.22x + 0.06 square units and its width is x + 0.2 unitsAnswer · 0 votesWelcome back. I am so glad you're here. We have a rectangle and we're told that the rectangle has an area of 0.7 X cubed minus 0.695 X squared minus 0.2 X plus 0.15 interesting area. But okay. We are told that the length of the rectangle is X plus 0. units and we are asked to find its width. Okay, well we know that the area of a rectangle is equal to the length times the width. And since we know the length we can substitute that in for our length. So we'll have X plus 0. times W is equal to this big long polynomial here. 0.7 X cubed minus 0.695, X squared minus 0.2 X plus 0.15. Okay well we've got ourselves an equation and now we can solve for w let's divide both sides by X plus 0.15. And on the right hand side that's not too bad because that X plus 0.15 just cancels out and all we're left with is a W. Great on the left. We just have to simplify so how do we simplify this? Well we just need to do the division and there are a lot of different ways to do the division but I suggest using …MoreStudy.comQuestionA rectangle with width 2x + 5 inches has an area of 2x4+9x3−12x2−79x−60 square inches. Write a polynomial that represents its length.Answer · 0 votesThe area of the given rectangle is, A=2x4+9x3−12x2−79x−60 square inches.Its width is given to be: w=(2x+5) inches.Let us assume that its length to be l inches.Substitute all these values in the formula of area of a rectangle:A=lw2x4+9x3−12x2−79x−60=l(2x+5)Dividing both sides by (2x+5),l=2x4+9x3−12x2−79x−602x+5Now we use long division to divide this.From the above long division, the length of the rectangle is, l=x3+2x2−11x−12 inches.MoreByju'sQuestionWrite a polynomial that represents the area of square-Answer · 0 votesSolve for the polynomial that represents the area of square:A polynomial is an expression of more than two algebraic terms, especially the sum of several terms .MoreWyzantQuestionWrite a polynomial that represents the area of the picture frames, not including the pictures.Answer · 0 votesA= 81 inch^2Now,A = L x W Also,So, we can write,81 inch^2 = L x Wtherefore,L= 81 inch^2/WidthMoreStack ExchangeQuestionLet K be a field; I will say a polynomial f∈K[X] represents an element a∈K if there exists a b∈K such that f(b)=a.Denote by Q, R and Qp the fields of rational, real and p-adic numbers respectively. Does there exist a polynomial f∈Q[X] such that• f represents only squares over R (but not all squares need to be represented),• f represents only squares over Q2 (but not all squares need to be represented),• for every prime number p>2, f does not represent only squares over Qp?If so, what is the minimal degree such a polynomial must have?What I have found so far:• A polynomial satisfying 1 and 3, but not 2:1+X2• A polynomial satisfying 1 and 2 and which I think might also satisfy 3, but I do not know how to prove it:(1+X2)(17+X2)Here, 17 may be replaced with any positive integer with residue 1 modulo 16.Answer · 6 votesClearly degree 1 and 3 polynomials do not satisfy property 1.The only degree 2 polynomials in Q[X] with property 2 are squares. To verify this, after a possible change of variables assume that aX2+b is a polynomial generating only squares over Q2 with b≠0. By setting X=0 we know b is a square in Q2, so multiplying by b−1 we can assume b=1. Next, write a=2nc with n=v2(a) its 2-adic valuation, so that c∈Z×2.• If n is even, say n=2m, set X=c21−m to find that 4c2+1 is a square in Q2, but we reach a contradiction as 5 is not a square modulo 8.• If n is odd, say n=2m−1, set x=2−m to yield that c/2+1 is a square in Q2, which is impossible because its valuation is −1.Finally, there do exist polynomials of degree 4 satisfying all three properties. In particular f(X)=(8X2+1)(8X2+9) does the job. Property 1 is clear, so let us check property 2.The (extended) Hensel's lemma tells you that if a polynomial in Q2[X] has a root modulo 8 whose derivative at that root is not divisible by 4, then…MoreMathOverflowQuestionIt's easy to tell when a polynomial is squarefree (or not): that's just the question of the vanishing of the discriminant, which can be dealt with as the resultant of f and f′. However, given a polynomial of degree 2n f, when is it of the form g2 for g a polynomial of degree n?I've been trying to work out the relations on the coefficients that will guarantee this for a specific degree (n=6 is my case) but whenever I take the obvious equations in the coefficients of g and of f and try to use Groebner bases to eliminate the coefficients of g, I run out of memory and my software crashes. Is there a way to understand the locus of polynomials which are squares concretely without having to do a (seemingly unrealistically) big computation? Or perhaps a clever trick that will give these polynomial identities in a more computable way?Answer · 14 votesSay, for simplicity, you are working over C or in characteristic zero in general. Then you can guess one of the two values of g(0) (say) and then compute the Taylor series of √f. The approach is similar to Hensel lifting: The equation for the first coefficient is non-linear; the equations for the others are all locally linear (so that you get explicit formulas for the coefficients of g in terms of existing data).I first misread Charles' question, but now that I have it right (I think), here is why I think that the above is still a solution. If you read the coefficients of a polynomial of degree n as projective coordinates, then over C the set of squares of degree 2n is some projective variety S in CP2n. Charles is interested in projective equations for this variety S.For simplicity let's rescale the polynomial f(x) so that f(0)=1. (And I guess we're working the affine chart in which f(0)≠0 before the rescaling. It shouldn't change things much or at all.) 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